Nd the 52nd term and the term named in the problem
40, 140, 240, 340, ...
Find a 32

5140 and 3140

Step-by-step explanation:

Note there is a common difference d between consecutive terms in the sequence, that is

d = 140 - 40 = 240 - 140 = 340 - 240 = 100

This indicates the sequence is arithmetic with n th term

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 40 and d = 100, thus

= 40 + (51 × 100) = 40 + 5100 = 5140

= 40 + (31 × 100) = 40 + 3100 = 3140