A line is perpendicular to y = 3x - 8
and intersects the point (2,2).
What is the equation of this
perpendicular line?

y=-1/3x+8/3

Step-by-step explanation:

y=3x-8 k1=3

k1*k2=-1

3*k2=-1

k2=-1/3

A(2,2) x1=2, y1 =2

y-y1 =k2(x-x1)

y-2=-1/3(x-2)

y-2=-1/3x+2/3

y=-1/3x+2/3+2

y=-1/3x+2/3+6/3

y=-1/3x+8/3

asdsad

step-by-step explanation:

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4