You are going to meet a friend at the airport. Your experience tells you that the plane is late 70% of the time when it rains, but is late only 20% of the time when it does not rain. What is the probability that the plane will be late?

0.4

Step-by-step explanation:

Probability of rain = P(R)

Probability of late plane = P(L)

So, the probability of no rain = P(R')

Breaking it down

If it rains, 40% chance, P(R) = 0.4

That the plane would be late if it rains = 70% × 40%, that is, P(R n L) = 0.7 × 0.4 = 0.28, 28% of the total chance.

That the plane would be on time if it rains = 30% × 40%, that is, P(R n L') = 0.3 × 0.4 = 0.12, 12% of the total chance.

If it doesn't rain, 60% chance, P(R') = 1 - P(R) = 1 - 0.4 = 0.6

That the plane would be late if it doesn't rain = 20% × 60%, that is, P(R n L') = 0.2 × 0.6 = 0.12, 12% of the total chance.

That the plane would be on time if it doesn't rain = 80% × 60%, that is, P(R' n L') = 0.8 × 0.6 = 0.48, 48% of the total chance.

So, probability that the plane would be late = P(L) = P(R n L) + P(R' n L) = 0.28 + 0.12 = 0.4 = 40%

answer: the answer is 127 degrees

10 you would take 50/ .2

step-by-step explanation: