What is the center of a circle whose equation is x2 + y2 – 12x - 2y + 12 = 0?
(-12, -2)
O (-6, -1)
(6, 1)
O (12, 2)

Solution:

Given equation of circle is:

Move the constant to other side

Group the equation

Add 36 and 1 from both sides

Which is simplified as:

--------- eqn 1

The equation of circle is given as:

Where, r is radius and (h, k) is center

Compare eqn 1 with above general equation

(h, k) = (6, 1)

Thus the center of a circle is (6, 1)

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: