A particle is moving horizontally along the x-axis. Its position (in ft) is: s(t)=t^3-18t^2+33t+14 where t is in sec.
Find the time at which the particle switches from moving left to moving right.
t= ___ sec.

t=11 sec

Step-by-step explanation:

The position of the particle moving along the x-axis is given by:

The velocity is given by:

If s'(t)>0 then the particle is moving right.

This means that the particle is moving left when

The particle changes direction at time t=1 or t=11

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step-by-step explanation:

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d