A)The equation of a line β is 2x-3y=6
find the gradient of β
b) find the equation of the line which is parallel to β and passes through the point (6,9)

a) 2/3

b)

Step-by-step explanation:

b) From my previous answer...

Since parallel lines have the same gradient,

the gradient of the line is 2/3 too.

Thus, m= 2/3.

y= 2/3x +c

Now substitute a coordinate into the equation to find c, the y-intercept.

When x=6, y=9,

9= (2/3)(6) +c

9= 4 +c

c= 9 -4

c= 5

Thus the equation of the line is y= 2/3x +5.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6