Mathematics, 04.03.2020 04:49 catuchaljean1623
Evaluation of Proofs See the instructionsfor Exercise (19) on page 100 from Section 3.1. (a) Proposition. If m is an odd integer, then .mC6/ is an odd integer. Proof. For m C 6 to be an odd integer, there must exist an integer n such that mC6 D 2nC1: By subtracting 6 from both sides of this equation, we obtain m D 2n6C1 D 2.n3/C1: By the closure properties of the integers, .n3/ is an integer, and hence, the last equation implies that m is an odd integer. This proves that if m is an odd integer, then mC6 is an odd integer
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Mathematics, 21.06.2019 13:20
Sherina wrote and solved the equation. x-56=230 x-56-56=230-56 x=174 what was sherina’s error? sherina’s work is correct. sherina only needed to subtract 56 from 230. sherina made a subtraction error when subtracting 56 from 230. sherina should have added 56 to both sides of the equation.
Answers: 2
Mathematics, 21.06.2019 16:30
Asequence {an} is defined recursively, with a1 = 1, a2 = 2 and, for n > 2, an = an-1 an-2 . find the term a241
Answers: 2
Evaluation of Proofs See the instructionsfor Exercise (19) on page 100 from Section 3.1. (a) Proposi...
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