Which of the following is not true? Choose the correct answer below. A. The area in any normal distribution bounded by some score x is the same as the area bounded by the equivalent z-score in the standard normal distribution. B. A z-score is a conversion that standardizes any value from a normal distribution to a standard normal distribution. C. A z-score is an area under the normal curve. D. If values are converted to standard z-scores, then procedures for working with all normal distributions are the same as those for the standard normal distribution.

A. The area in any normal distribution bounded by some score x is the same as the area bounded by the equivalent z-score in the standard normal distribution - false

B. A z-score is a conversion that standardizes any value from a normal distribution to a standard normal distribution - True

Step-by-step explanation:

A. The area in any normal distribution bounded by some score x is the same as the area bounded by the equivalent z-score in the standard normal distribution- This statement is false in the sense that it is a point that is equivalent to corresponding point of normal distribution.

B. A z-score is a conversion that standardizes any value from a normal distribution to a standard normal distribution.  - This statement is true in the sense that z-score is in the normal standard distribution.

C. A z-score is an area under the normal curve - This statement is true in the sense that z-score is a conversion that standardizes any value from a normal distribution to a standard normal distribution.

D. If values are converted to standard z-scores, then procedures for working with all normal distributions are the same as those for the standard normal distribution - This statement is absolutely true

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: