A projectile is fired vertically into the air. Its motion is described by
h = -16t2 + 320t, where h is the projectile’s height (in feet) after t seconds.

a. During what time interval(s) will the height of the projectile be below 1024 feet?
b. During what time interval(s) will the height of the projectile be above 1024 feet?

6 meters

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

combine all like terms then its just a 2 step equation