Select two points that the line would go through. Practice graphing it on a piece of paper in front of you.

Graph the line that passes through the point (3, -1) and has a y-intercept of -4.

(1, -3)

(4, 1)

(6, 3)

2, -2)

I need a step by step explanation if possible, I am having trouble on this topic

(2, -2) and (1,-3)

Step-by-step explanation:

The y-intercept means that the coordinate where the line touches the y-axis. In other words, the y value(-4) when x=0. The result is (0, -4). The y coordinate also can be used to fill c variable of y=mx + c

We have 2 coordinates now, (3, -1) and (0, -4), then we can find out the line equation. We need to find the slope (m), the formula will be:

m= y2-y1 / x2-x1=  

m= -4 - (-1) / (0-3)

m= -3/-3= 1

The line equation is:

y= mx + c

y= 1x + (-4)

y= x-4

After you have the equation, you can try to test the point individually to find if any of them fit the equation. You can also draw a line on the graph and see if any point touches the graph.

Red dot is the two point we have, red line is straight line that made from both point, and blue point is the option. As you can see on the graph, the points that touch the line will be (2, -2) and (1,-3)

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?