How many ways can three items be selected from a group of six items? Use the letters A, B, C, D, E, and F to identify the items, and list each of the different combinations of three items. (Enter your answers as a comma-separated list. Enter three unspaced capital letters for each combination.)

Three items can be selected from six items using combination formula            C (n , k) = C (6 , 3) , in 20 ways

C (n, k) = n ! / (n - k) !

6 c 3 = 6 ! / 3 ! (6 - 3) !

= 6! / 3! 3!

= [ 6 x 5 x 4 x 3 x 2 x 1 ] / [ 3 x 2 x 1 x 3 x 2 x 1 ]

= 5 x 4

= 20 ways

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20 ways

Step-by-step explanation:

6C3 = 20

(A,B,C)

(A,B,D)

(A,B,E)

(A,B,F)

(A,C,D)

(A,C,E)

(A,C,F)

(A,D,E)

(A,D,F)

(A,E,F)

(B,C,D)

(B,C,E)

(B,C,F)

(B,D,E)

(B,D,F)

(B,E,F)

(C,D,E)

(C,D,F)

(C,E,F)

(D,E,F)

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35