Susie school is due west of her house into south of her friend Alana‘s house. The distance between the school and Alana‘s house is 5.6 miles in the straight line distance between Susie's house in Alanna‘s house is 8.7 miles. How far is Susie's house from school?

(See the attached diagram.)

We know one leg of a right triangle as well as its hypotenuse. We need to find the other leg using the Pythagorean Theorem.

The Pythagorean Theorem states that , where and are the legs and is the hypotenuse.

Insert the known values into the equation. The distance between Susie's house and the school will be represented by .

Convert the decimals to fractions.

To raise a fraction to a power, raise both the numerator and the denominator to that power.

Multiply both sides of the equation by .

Subtract from both sides.

Subtract.

Divide both sides by .

Take the square root of both sides.

Susie's house is 6.9 miles from school

Step-by-step explanation:

The distance between Susan's house, her school and Alana‘s house forms a right angle triangle. In the right angle triangle, the distance between Alana's house and the school represents the hypotenuse of the right angle triangle while the opposite and adjacent sides are the distances between Susie's house and her school and as well as the distance between Susie's house and Alana's house.

To determine the distance between Susie's house and her school h, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore

8.7² = 5.6² + h²

h² = 75.69 - 31.36 = 44.33

h = √44.33

h = 6.9 miles

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)