Suppose you buy 4 buckets of apples and 5 buckets of peaches for $64. If you bought 8
buckets of apples and 3 buckets of peaches, you would have spent $72. How much is one
bucket of apples (a), and one bucket of peaches (p)?
A. a = $8, p = $3
B. a = $4, p = $5
C. a = $8, p = $6
D. a = $6, p = $8

Option D is the correct answer.

Step-by-step explanation:

Step 1 :

Let A represent the cost of one bucket of apple and P represent the cost of one bucket of peaches.

So we have ,

4 buckets of apples and 5 buckets of peaches for $64

8  buckets of apples and 3 buckets of peaches for $72

Writing this in the equation form we have,

4A + 5P = 64

8A + 3P = 72

Step 2:

Solving for the above 2 equations we can get the required costs

Equation 1 is

4A + 5P = 64 , Multiplying this by 2 we have 8A + 10P = 128

Equation 2  = 8A + 3P = 72

Subtracting both we have , 7p = 56 = > P = 8

Substituting this in equation 1 we have

8A + 80 = 128 => A = 6

Hence the cost of one bucket of apple is $6 and the cost of one bucket of apple is $8.

Option D is the correct answer.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

black lol

step-by-step explanation:

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i can tell you jamal now has 3 cookies xd

tommy has 2.

this made me lol.