In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two independent random samples were selected and the following statistics were calculated. Downtown Store - North Mall Store Sample size: 25 - 20 Sample mean: $9 - $8 Sample standard deviation: $2 - $1A 95% interval estimate for the difference between the two population means is
a. 1.09 to 4.08
b. 0.07 to 1.9
c. 1.08 to 2.92
d. 1.9 to 2.08

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

X[bar]₂= $8

S₂= $1

Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ±

Sa= 1.64

(9-8)±2.017*

[0.007636;1.9923]

I hope it helps!

step-by-step explanation:

ask goog great chance of finding the solution there

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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