Suppose bug A lands on the end of the blade farthest from the pivot. Assume the wiper turns through an angle of 120°. In one cycle (back and forth) of the wiper blade, how far has the bug traveled?

s = 21.33*π in

Step-by-step explanation:

Given:

- The complete data is given in the figure (attached):

Solution:

- The bugs lands on the end of the wiper blade furthest to the pivot. The arc length (s) swept by a wiper in one cycle i.e θ = 120° would be given by:

                                    s = 2*r*θ

- Where, r: The distance between the bug and the pivot = 16 in  

              θ : Angle swept in radians

- The distance travelled by the bug is s:  

                                   s = 2*(16)*( 120 / 180 ) * π  

                                   s = 21.33*π in

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =