Baby Grace Graph -
a) Use the data in the table to find the rate of change in the length of baby girl Grace.
b) Write a linear equation for the graph in point-slope form. Show your work.
c) Use your equation to determine how long Grace was at birth. Show your work and
explain how you can check your result using your knowledge of rate of change.
d) Based on the data, how long do you predict baby Grace will be at 36 months of age? Use the rate of change to justify your answer. Does your answer make sense?
Explain.

Baby Claire Graph -
a) Determine the slope of the line. Show your work.
b) Is baby girl Claire growing at a faster rate than baby girl Grace? Justify your answer.
c) Use point-slope form to write a linear equation to represent the growth of Claire overtime. Then, simplify the equation and write it in slope-intercept form. Identify the y-intercept. Show your work.
d) Based on the data, how long was Claire at birth? Explain.

The table and the graph both illustrate a linear function

(a) The rate of change

Select any two points from the given table

The rate of change (m) is:

The rate of change is 0.75 inches per month

(b) The linear equation

The equation in point slope form is:

So, we have:

(c) Her length at birth

At birth, the number of months is 0

i.e. x = 0

So, we have:

Solve for y

Her length at birth was 17 inches

(d) Her length in 36 months time

This means that: x = 36

So, we have:

Solve for y

Her length in 36 months will be 44 inches

(a) The slope

Select any two points from the given graph

The rate of change (m) is:

The slope is 2 inches per month

(b) Compare their growing rates

Baby Grace growing rate is 0.75 inches per month

Baby Clair growing rate is 2 inches per month

By comparison,

Baby Clair has a faster growing rate

(c) The linear equation

The equation in point slope form is:

So, we have:

(d) Her length at birth

This means that: x = 0

So, we have:

Solve for y

Her length at birth was 14 inches

Read more about linear equations at:

link

a) 0.75 inch/month

b) y-20 = 0.75(x-4)

c) 17 inches

d) 44

a) 0.8 inch/month

b) yes

c) y = 0.8x + 18.8

d) 18.8 inches

Step-by-step explanation:

a) (21.5-20)/(6-4) = 1.5/2

= 0.75 inch/month

If this is correct, 2 months after the 6th month (month 8), it should be

21.5 + 2(0.75) = 23

Which it is

b) y-y1 = m(x-x1)

Where y is the length, x is the months, m is the slope and (x1,y1) is a known point

At x = 4, y = 20

y-20 = 0.75(x-4)

Or

y = 0.75x + c

20 = 0.75(4) + c

c = 20 - 3 = 17

y = 0.75x + 17

c) at birth, 4 months before month 4

So, 20 - 0.75(4) = 17

Which is also the y-intercept

d) y = 0.75(36) + 17

y = 27 + 4 = 44 inches

Generally, at the age of 3 years (36 month) the length is between 35 and 40 inches

a) slope = (30-22)/(14-4)

= 0.8 inch/month

b) 0.8 > 0.75, so yes

c) When x = 4, y = 22

y-22 = 0.8(x - 4)

y - 22 = 0.8x - 3.2

y = 0.8x + 18.8

y-intercept is 18.8

d) at birth, x = 0.

Length was 18.8 inches

the answer is c. 23/3

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!