An object is thrown upward from the top of an 80-foot building with an initial velocity of 64 feet per second. The height h of the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 64 t plus 80. When will the object hit the ground?

Step-by-step explanation:

Solving:

Use the formula h = -16t^2 +vt +s

What we know:

v = 64 feet per second (initial velocity)

s = 80 foot (initial height)

h = ?

t ?

h = -16t^2 + 64t + 80

I know I should be asking in detail, are you allowed to use the quadratic formula or solve it by factoring it out?

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.

she drove 134 miles

step-by-step explanation: