A city park is in the shape of a rectangle with width of 25 yd, and length of 60 yd. What is
the length of the diagonal that runs across the park?
A) V85 yd.
B) 85 yd.
C) V2975 yd.
D) 65 yd.

The length of the diagonal that runs across the park is 65 yd

Step-by-step explanation: The dimensions of the city park has been given as 60 yd by 25 yd. The line that forms the diagonal across the park helps to create a right angled triangle with two sides given as 60 and 25. The third side, which is the diagonal (also called the hypotenuse) is yet unknown.

Having a right angled triangle with two sides we can use the Pythagoras theorem given as

AC^2 = AB^2 + BC^2

(That is, AC squared equals AB squared plus BC squared)

AC is the diagonal/hypotenuse while AB and BC are the other two sides. Hence, the formula becomes

AC^2 = 60^2 + 25^2

AC^2 = 3600 + 625

AC^2 = 4225

Add the square root sign to both sides of the equation and we have

AC = 65

Therefore the length of the diagonal is 65 yd.

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

step-by-step explanation: