To rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $6 per hour. The chemistry club wants to spend at most on renting the room. What are the possible numbers of hours the chemistry club could rent the meeting room?

Use t for the number of hours.
Write your answer as an inequality solved for t.

To spend at most $93, they need to rent the room less than or equal 13 hours.

Step-by-step explanation:

The complete question is

To rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $6 per hour. The chemistry club wants to spend at most $93 on renting a room. What are the possible numbers of hours the chemistry club could rent the meeting room? Use t for the number of hours. Write your answer as an inequality solved for t,

Let

t ----> the number of hours

we know that

I this problem the word "at most" means "less than or equal to"

The number of hours rented multiplied by the cost per hour, plus the reservation fee, must be less than or equal to $93

so

The inequality that represent this situation is

solve for t

subtract 15 both sides

Divide by 6 both sides

therefore

To spend at most $93, they need to rent the room less than or equal 13 hours.

coins of silver or gold

step-by-step explanation:

so, converting firstly the mixed fractions to improper fractions and then "adding".