How many solutions does the system have?
6x - y = -1
6x+y=-1

x = - 1/6

y = 0

Step-by-step explanation:

It can be solved simultaneously

6x - y = -1

6x + y = -1

Subtract equation two from equation one

-2y = 0

Divide both sides by-2

y = 0/-2

y = 0

Substitute 0 for y in either of the equations to get x

Using equation one , we have

6x - 0 = -1

6x = -1

Divide both sides by 6

x = -1/6

c: lkllmn.

hope it's you

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15