If (x + 1/x)^2 = 3 what is the value of x^3 + 1/x^3

(x + 1/x)² = 3                 | √

x + 1/x = √3

According to short multiplication formula:

(a + b)³ =a³ + 3a²b + 3ab² + b³

x³ + 1/x³ = (x)³ + (1/x)³ = (x + 1/x)³ - 3x²/x - 3x/x² =

=  (x + 1/x)³ - 3x - 3/x = (x + 1/x)³ - 3(x + 1/x) =

= (√3)³ - 3√3 = 3√3 - 3√3 = 0

If (x + 1/x)² = 3 the value of x³ + 1/x³ is 0.

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

answer: i think it is (1,-2)