Consider the equation below. x2 − y2 + z2 − 6x − 2y − 2z + 9 = 0 Reduce the equation to one of the standard forms. Classify the surface. ellipsoid hyperboloid of one sheet circular cone elliptic paraboloid hyperboloid of two sheets hyperbolic paraboloid elliptic cylinder parabolic cylinder Sketch the surface.

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Step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

i dont understand the question? ?

step-by-step explanation: