The distribution of certain test scores is a nonstandard normal distribution with a mean of 50 and a standard deviation of 6. What are the values of the mean and standard deviation after all test scores have been standardized by converting them to z-scores using z = (x - µ) / σ ?Select one:a. The mean is 0 and the standard deviation is 0.5.b. The mean is 0 and the standard deviation is 1.c. The mean is 10 and the standard deviation is 100.d. The mean is 100 and the standard deviation of 10.e. The mean is 1 and the standard deviation is 0.

b. The mean is 0 and the standard deviation is 1

Step-by-step explanation:

When the test score are standardized, they follow the standard normal distribution. The main feature of standard normal distribution is that it has zero mean and unit variance. So, when the test scores standardized by converting them to z-scores, the values of mean and standard deviation of standardized test scores are 0 and 1.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: