Mathematics, 28.02.2020 19:01 Theacefamily123

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each quadratic equation with its solution set. arrowRight arrowRight arrowRight arrowRight

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each qu

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Answer from: romanlittlewood

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.We have to solve all of the five equations to be able to match the equations with their solutions.2x² - 8x + 5, here a = 2, b = -8, c = 5. x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4. 24 can also be written as 4 × 6 and √4 = 2. So x = 8 ± 2√6 / 2×2= 4±√6/2.2x² - 10x + 3, here a = 2, b = -10, c = 3. x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.2x² - 8x - 3, here a = 2, b = -8, c = -3. x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4. 88 can also be written as 4 × 22 and √4 = 2. So x = 8 ± 2√22 / 2×2 = 4± √22/2.2x² - 9x - 1, here a = 2, b = -9, c = -1. x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4. x = 9 ± √89 / 4.2x² - 9x + 6, here a = 2, b = -9, c = 6. x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4. x = 9 ± √33 / 4 .

Answer from: holmesleauja

The right solutions that matches each of the given quadratic equations are;

(9 ± √33)/4 → 2x² - 9x + 6.

(4 ± √6)/2 → 2x² - 8x + 5

(9 ± √89)/4 → 2x² - 9x - 1

(4 ± √22)/2 → 2x² - 8x - 3.

The formula to find the roots of a quadratic equation of the form, ax² + bx + c = 0 is;

x = [-b ± √(b² - 4ac)]/2a

where;

a, b, and c are the coefficients of the x², x, and the numeric term respectively.

Applying the quadratic formula to the given quadratic equations;

1) 2x² - 8x + 5;

x = [-(-8) ± √(-8)² - 4(2)(5)]/(2(2))

x = [8 ± √(64 - 40)]/4

x = [8 ± √(24)]/4

x = (8 ± 2√6)/4

x = (4 ± √6)/2

2) 2x² - 10x - 3

x = [-(-10) ± √((-10)² - 4(2)(-3))]/2(2)

x = [10 ± √(100 + 24)]/4

x = [10 ± √(124)]/4

x = (10 ± 2√31)/4

x = (5 ± √31)/2

3) 2x² - 8x - 3

x = [-(-8) ± √((-8)² - 4(2)(-3))]/2(2)

x = [8 ± √(64 + 24)]/4

x = [8 ± √(88)]/4

x = [8 ± 2√(22)]/4

x = (4 ± √22)/2

4) 2x² - 9x - 1

x = [-(-9) ± √((-9)² - 4(2)(-1))]/2(2)

x = [9 ± √(81 + 8)]/4

x = (9 ± √89)/4

5) 2x² - 9x + 6

x = [-(-9) ± √((-9)² - 4(2)(6))]/2(2)

x = [9 ± √(81 - 48)]/4

x = (9 ± √33)/4

Read more about quadratic formula at; link

Answer from: Quest

question:

could we have options?

Answer from: Quest

idk lol

step-by-step explanation:

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