Slope of the line is
.
x-intercept is 0 and the y-intercept is 0.
direct variation equation  relating x and y is
.
Solution:
Let the points on the line are (–3, 2) and (3, –2).
![x_1=-3, y_1=2, x_2=3, y_2=-2](/tpl/images/0527/9165/33e50.png)
Slope of the line:
![$m=\frac{y_2-y_1}{x_2-x_1}](/tpl/images/0527/9165/53e56.png)
![$m=\frac{-2-2}{3-(-3)}](/tpl/images/0527/9165/24f52.png)
![$m=\frac{-4}{3+3}](/tpl/images/0527/9165/8f172.png)
![$m=\frac{-4}{6}](/tpl/images/0527/9165/ded7c.png)
![$m=\frac{-2}{3}](/tpl/images/0527/9165/497dd.png)
Slope of the line is
.
The x-intercept is, where a line crosses at x-axis.
The y-intercept is, where a line crosses at y-axis.
Here, x-intercept is 0 and the y-intercept is 0.
Direct variation form:
y = mx
![y=\frac{-2}{3}x](/tpl/images/0527/9165/e7960.png)
Hence slope of the line is
.
x-intercept is 0 and the y-intercept is 0.
direct variation equation  relating x and y is
.