White vinegar is a solution of acetic acid in water. There are two strengths of white vinegar, 5% solution and a 10% solution. How many milliliters of each solution must be mixed to make 50 mL of a 9% solution?

10mL of the 5% solution and 40mL of the 10% solution

Step-by-step explanation:

To get the amount of each solution in milliliters that must be mixed to male 50ml of a 9% solution,

First let us represent the amount of 5% solution as A

Furthermore, let us represent the amount of 10% solution as B

From the question we know that A + B = 50ml

Hence 5% = 0.05 and 10% = 0.10

Then we get

0.05A + 0.10B = 0.09(A+B)

Then we solve further to get

Also, from A+B=50

A = 50 - B

0.05(50 - B) + 0.1B = 0.09(50 - B + B)

2.5 - 0.05B + 0.1B = 4.5

0.05B = 2

B = 40mL

And we know that A+B = 50,

Hence

40+A = 50

A= 50-40 = 10mL

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.

a

step-by-step explanation: