A personnel director interviewing 12 senior engineers for five job openings has scheduled seven interviews for the first day and five for the second day of interviewing. Assume that the candidates are interviewed in a random order.

(a) What is the probability that x of the top four candidates are interviewed on the first day?
h(N; 5, 5, 12) h(x; 5, 12, 5) h(N; 7, 12, 5) h(x; 7, 5, 12)
(b) How many of the top four candidates can be expected to be interviewed on the first day? (Round your answer to two decimal places.)

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

it is a secret for it not to be compromised sorry

step-by-step explanation: