Xue Ying had 143 more sweets than Joanne. After Joanne gave away 22 sweets, Xue Ying had 6 times as many sweets as Joanne. How many sweets did Joanne have in the end?

In the end Joanne had 55 sweets.

Step-by-step explanation:

Let the number of sweets that Xue Ying had be y and let the number of sweets Joanne had be x.

It is given that Xue Ying had 143 more sweets than Joanne. We can write this information as an equation.

               y = x + 143.

It is also given that Joanne gave away 22 of her sweets and after that Xue Ying had 6 times as many more sweets. We can write this as an equation.

             y = 6(x - 22) = 6x - 132.

Therefore we can equate the two equations and solve for x.

                 x + 143  = 6x  - 132

                5x  = 275

        ∴       x =   sweets.

Therefore in the end Joanne had 55 sweets.                        

if you was gonna solve for a, a is a   < -12

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step-by-step explanation: