A computer is printing out subsets of a 6 element set (possibly including the empty set). (a) At least how many sets must be printed to be sure of having at least 3 identical subsets on the list? Answer = (3*6!)+1 (b) At least how many identical subsets are printed if there are 257 subsets on the list?

(a) 129

(b) 5

Step-by-step explanation:

(a) In a set with elements, the number of possible distinct subsets is .

For a 6-element set, this number is .

The minimum for two identical subsets will be 1 + 64 = 65, since 64 already contains all possible subsets. Any extra subset will be identical to one of them.

For three identical subsets, all subsets must have been repeated twice. Any extra is then repeated thrice. Hence, we have 64 × 2 + 1 = 129

(b) With 257 subsets, we first determine how many times each distinct subset could have been repeated by dividing 257 ÷ 64 = 4 with a remainder of 1. This means possibly, all subsets have been repeated 4 times. The extra 1 makes it a fifth time for one of them. So, the minimum number of identical subsets is 5.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

answer: its the third option.

step-by-step explanation:

i just took the test.