A farmer had a farm with animals.

ANIMALS:
15 cows
8 chickens
20 pigs
3 birds
18 sheep
5 horses

PART A: How many cows, sheep, pigs, and chickens does the farmer have all together?

PART B: If the farmer adopted 29 more horses, how many animals would he have in total now?

PART C: If the farmer sold 1/2 of his animals, how many would he have then?

PART A: 61

PART B: 98

PART C: 49

Step-by-step explanation:

PART A: 15+8+20+18 = 61

PART B: 29+69 = 98

PART C: 98/2 = 49

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic