In ΔJKL, \overline{JL} JL is extended through point L to point M, m∠JKL = (2x+14)^{\circ}(2x+14) ∘ , m∠LJK = (3x+15)^{\circ}(3x+15) ∘ , and m∠KLM = (7x+9)^{\circ}(7x+9) ∘ . What is the value of x?

The value of x for the given triangle JKL is 10.

Given information:

In ΔJKL, JL is extended through point L to point M.

See the attached figure.

At point L, the measure of angle JLK will be as,

Now, in triangle JKL, use the angle sum property to find the value of x as,

Therefore, the value of x for the given triangle JKL is 10.

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The value of x =10°

Step-by-step explanation:

Check attachment for solution.

Triangle theorem: the sum of the opposite interior angle is equal to the exterior angle.

<JKL+<LJK=<KLM

2x+14+3x+15=7x+9

Collect like terms

2x+3x-7x=9-14-15

-2x=-20

Divide both side by -2

x=10°

step-by-step explanation:

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