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For what value of x does 3 Superscript 2 x Baseline = 9 Superscript 3 x minus 4?
a. 1
b. 2
c. 3
d. 4
Answers: 3
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Find the directions in which the function increases and decreases most rapidly at upper p 0p0. then find the derivatives of the function in these directions. f(x,y)equals=x squared plus xy plus y squaredx2+xy+y2, upper p 0p0left parenthesis 1 comma negative 4 right parenthesis
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For what value of x does 3 Superscript 2 x Baseline = 9 Superscript 3 x minus 4?
a. 1
...
a. 1
...
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