For what value of b does (one-twelfth) Superscript negative 2 b Baseline times 12 Superscript negative 2 b + 2 Baseline = 12?

a. Negative one-half
b. Negative one-fourth
c. One-fourth
d. no solution

Option d. No solution

Step-by-step explanation:

The rules of exponents are:

Given:

(one-twelfth) Superscript negative 2 b Baseline times 12 Superscript negative 2 b + 2 Baseline = 12

The algebraic expression for the given problem is:

The base of the left hand side = The base of the right hand side

So, the exponents of the two sides will be equal.

∴ 2b - 2b + 2 = 1

∴ 2 = 1 (rejected because un-logic condition)

So, the answer is d. No solution

3, nah jk it's 2

step-by-step explanation:

it is 3 cause i'm sanic

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