What is the equation of the line that passes through points (-3, 0.5) and (3, 0.5

y = 0.5

Step-by-step explanation:

y = mx + b

m = (y2-y1)/(x2-x1)

m = (0.5 - 0.5)/(3-(-3))

m = 0/6

m = 0

y = mx + b

y = 0x + b

0.5 = 0(3) + b

b = 0.5

therefore

y = 0x + 0.5

y = 0.5

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.