Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (0,0) be defined to be .

f(0,0)=ln19

Step-by-step explanation:

is given as continuous function, so there exist and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

we know that , so we have that

So f(0,0)=ln19.

step-by-step explanation:

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(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3