Researchers are interested in determining whether more men than women prefer Coca Cola to Pepsi. In a random sample of 300 men, 65% prefer Coca Cola, whereas in a random sample of 400 women, 48% prefer Coca Cola. What is the 99% confidence interval estimate for the difference between the percentages of men and women who prefer Coca Cola over Pepsi? 0.17 ± 0.036 0.17 ± 0.096 0.17 ± 0.067 0.565 ± 0.067 0.565 ± 0.096

0.17±0.096

Step-by-step explanation:

p1=0.65

p2=0.48

The 99% confidence interval can be calculated as

q1=1-p1=1-0.65=0.35

q2=1-p2=1-0.48=0.52

n1=300

n2=400

0.17±0.096

Thus, the 99% confidence interval estimate for the difference between the percentages of men and women who prefer Coca Cola over Pepsi is 0.17±0.096

1760 kilometers

step-by-step explanation:

multiply the amount of time the plane took to travel by it's speed

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get