Solve this problem.
The length of the smaller rectangle at the right is 1 inch less than
twice its width. Both the dimensions of the larger rectangle are 2
inches longer than the smaller rectangle. The area of the shaded
region is 86 square inches. What is the area of the larger
rectangle?

Let x = the width of the smaller rectangle.

The length of the smaller rectangle is 2x - 1.

Area is A = lw

So the area of the smaller rectangle is A = (x)(2x - 1) = 2x^2 - x

Step-by-step explanation:

hope it helped

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

answer: b

step-by-step explanation: