Find the missing angle measures of 2 and 3. Plz help

For #2.

All of the angles are measured x. They are all the same so they must equal each other.

So,

x = 60°

Because 60 + 60 + 60 = 180° and 60° = 60°.

For #3

Three angles should add up to 180 since it is the total angle.

n + 1/2n + 1/2n = 180

Solve for n:

n + n = 180

2n = 180

n = 180 ÷ 2

n = 90°

1/2 n

1/2 (90) = 45°

1/2 n = 45°

2) x=60°

they have labelled all 3 x, which means that it's an equilateral triangle, all angles are equal, and all sides are equal

3)

this is an isosceles triangle, since 2 of the sides are equal 1/2 (n).

so n+n=180

this triangle has a right angle, angle ZXY (X)

so n= 90

90+90=180

90+(1/2*(90)*2)=180

90+(45*2)=180

∠ZXY=90°

∠YZX and ∠ZYX = 45°

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

14 ft 7 inches

step-by-step explanation:

since each model inch corresponds to 25 real inches, 7 model inches will correspond to

7×25" = 175"

at 12" per foot, that is 14 feet, 7 inches.