As a result of friction, the angular speed of a wheel c hanges with time according to d θ d t = ω0 e −σ t , where ω0 and σ are constants. The angular speed changes from an initial angular speed of 4.43 rad/s to 3.63 rad/s in 3.92 s. Determine the magnitude of the angular acceleration after 3.41 s. Answer in units of rad/s 2 .

The value of angular acceleration after 3.41 s is -0.18925 rad/s^2

Step-by-step explanation:

As per the given data the value is given as

Where

Now as the acceleration is given as

As  values of

thus acceleration is given as

So the value of angular acceleration after 3.41 s is -0.18925 rad/s^2

(a) the volume of the cone is 20/3 in3

hence, option a is correct.