Arla and kal both work in jobs where they get paid by the hour in their first week on the job they each worked 40 hours and together

Question is Incomplete;Complete question is given below;

Arla and kal both work in jobs they get paid by the hour in their first week on the job they each worked 40 hours and together there total earnings were $1300 in their second week on the job business was slow so arla worked 20 hours and kal worked 16 hours their total pool earning was $580 what is each persons hourly wage.

The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.

Step-by-step explanation:

Let the hourly wage of Arla be

Also Let the hourly wage of Kal be

Now Given:

first week on the job they each worked 40 hours and together there total earnings were $1300

So we can say that;

  ⇒ equation 1

Also Given:

Number of hours worked by Arla in second week = 20

Number of hours worked by Kal in second week = 16

Total Money earned in second week = $580

So we can say that;

  ⇒ equation 2

Now Multiplying equation 2 by 2 we get;

Applying Distributive property we get;

  ⇒ equation 3

Now Subtracting equation 3 from equation 1 we get;

Now Dividing both side by 8 we get;

Now Substituting the value of y in equation 1 we get;

Hence The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.