Solve Laplace’s equation inside a rectangle 0 ≤ x ≤ L, 0 ≤ y ≤ H, with the following boundary conditions. [Hint: Separate variables. If there are two homogeneous boundary conditions in y, letu(x, y)=h(x)φ(y), and if there are two homogeneous boundary conditions in x, letu(x, y)=φ(x)h(y).]:

∂u /∂x (0,y) = 0,

∂u /∂x (L, y) = 0,

u(x,0) = 0,

u(x, H)=f(x)

answ9x x 3=

step-by-step explanation:

2.56 is the width of the garden

step-by-step explanation:

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.