Four oranges and five apples cost $3.56. Three oranges and four apples cost $2.76. Find the cost of an orange and an apple using system of equations

Cost of oranges = $0.44

Cost of apples = $0.36

Step-by-step explanation:

Assume:

Cost of oranges = a

Cost of apples = b

4a + 5b = $3.56 (1)

3a + 4b = $2.76 (2)

from equation (1),

4a = $3.56 - 5b

a = ($3.56 - 5b) ÷ 4 (3)

Input equation (3) in equation (2)

3 * [($3.56 - 5b) ÷ 4] + 4b = $2.76

$2.67 - 3.75b + 4b = $2.76

0.25b = $2.76 - $2.67 = $0.09

b = $0.09 ÷ 0.25 = $0.36

Therefore, a = ($3.56 - (5 * $0.36)) ÷ 4 = $0.44

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

$18 was the price of the t-shirt

step-by-step explanation: