The function A(s) given by A(s)equals0.328splus50 can be used to estimate the average age of employees of a company in the years 1981 to 2009. Let A(s) be the average age of an employee, and s be the number of years since 1981; that is, sequals0 for 1981 and sequals9 for 1990. What was the average age of the employees in 2003 and in 2009?

Step-by-step explanation:

We are given the function A(s) as;

           A(s) = 0.328*s + 50   where s = number of years since 1981; that is,

                                                   s = 0 for 1981 and s = 9 for 1990

A(s) = the average age of an employee

        Here s = 22 because 2003 - 1981 = 22 years

Therefore, average age of the employees in 2003 = 7.216 + 50 = 57.216 .

        Here, s = 28 because 2009 - 1981 = 28 years

Therefore, average age of the employees in 2009 = 9.184 + 50 = 59.184 .

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

45

step-by-step explanation: