Car X and car Y traveled the same 80-mile route. If car X took 2 hours and car Y traveled at an average speed that was 50 percent faster than the average speed of car X, how many hours did it take car Y to travel the route?

Step-by-step explanation:

Both cars, X and Y travelled 80 miles each.

Speed = distance/time

If car X took 2 hours to travel 80 miles, it means that the speed at which car X travelled is

80/2 = 40 mph

If car Y traveled at an average speed that was 50 percent faster than the average speed of car X, it means that the speed at which car X travelled is

40 + 0.5 × 40 = 60 mph

Time = distance/speed

Therefore, time taken by car Y to travel 80 miles is

80/60 = 1.33 hours

answer: d. $20

step-by-step explanation:

just took the test

the answer is simply just 6n add the two together as they have an n