Find algebraically in RxR using substituting method the S. S. of the two equations:
X + y = 4
,
2 x - y = 5

Step-by-step explanation:

x + y = 4   equation 1

2x - y = 5  equation 2

using substitution method,

x= 4 - y  equation 3

substitute equation 3 into equation 2

2(4-y) -y = 5

8 - 2y - y = 5

8 - 3y = 5

-3y = 5 - 8

-3y = -3

divide through by -3

-3y/-3 = -3/-3

y = 1

substitue the value of y into equation 1

x + y = 4

x + 1 = 4

x = 4 - 1

x = 3

Hence, x = 3 and y = 1

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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