Find the equation of the line that passes through (1,0) and is parallel to y=-3x-1
Show full working out ty

y = -3x + 3

Step-by-step explanation:

Parallel lines have the same slope.

The given line has a slope of -3, its parallel line will also have a slope of -3... m = -3

y = -3x + c

When x = 1, y = 0

0 = -3(1) + c

c = 3

y = -3x + 3

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: