IQ scores for adults age 20 to 34 years are normally distributed according to N(120, 20). About what percent of people in this group scored above 140?

68%
34%
16%
13.5%
2.5%

16%

Step-by-step explanation:

Since the IQ scores for adults age 20 to 34 years are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = IQ scores for adults age 20 to 34 years.

µ = mean score

σ = standard deviation

From the information given,

µ = 120

σ = 20

We want to find the probability of people in this group scored above 140. It is expressed as

P(x > 140) = 1 - P(x ≤ 140)

For x = 140,

z = (140 - 120)/20 = 1

Looking at the normal distribution table, the probability corresponding to the z score is 0.84134

P(x > 140) = 1 - 0.84134 = 0.15866

Approximately 0.16

Therefore, the percent of people in this group scored above 140 is

0.16 × 100 = 16%

c: lkllmn.

hope it's you

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.