WILL REWARD BRAINLIEST
Two ships leave port at the same time. One heads due north and the other heads due east. Later, the two boats are exactly 100 km apart. The ship headed north has traveled 20 km farther than the ship going east. How far has the ship going east traveled?

answer:

OAB is a right triangle with the hypotenuse AB = 100 km. Let x be OB, the distance travelled East, the distance OA travelled North is x+20 (given)

Now apply Pythagoras:AB² = OA² + OB² ↔ 100² = (x+20)² + x²After expanding you'll find:2x²+40x-9600 = 0. Solve this quadratic equation and you will find :x' = 60 and x" = -80 (extraneous). Hence OB = x = 60 km

-Hops

answer: i can’t tell you that

step-by-step explanation:

idc

step-by-step explanation:

idk