The area of a triangle block is 64 square inches if the base of the triangle is twice the high how long are they base and the height of the triangle

The height is 8 and the base is 16

Step-by-step explanation:

the area of a triangle is bh, where b is the length of the base, and h is the length of the height.

We are given that the base is twice the height, so b=2h. If we substitute b for 2h in our equation, we get that the area of the triangle is (2h)(h), which equals h^2.

Therefore, the area of this triangle is h^2. We are given that the area is 64, so h^2=64. The only positive value for h is 8, so h=8.

Since b=2h, b=2*8=16, so the height is 8 and the base is 16

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

16.80 times .20= 3.36

step-by-step explanation: