F. A restaurant chef prepares a tossed salad containing, on average, 5 vegetables per day. Find the probability that the salad contains more than 7 vegetables on i) a given day and on ii)3 of the next 6 days?

Step-by-step explanation:

Given that a restaurant chef prepares a tossed salad containing, on average, 5 vegetables per day.

We can assume the number of vegetables used by the chef per day is

Poisson with parameter = mean = 5

We are to find the probability that the salad contains more than 7 vegetables on i) a given day and on ii)3 of the next 6 days?

a) P(no of vegetables >7) = 1-F(7) = 1-0.8666

=0.1334

b) For 6 days we can say each day is independent of the other

Prb( veg >3) for 6 days

= P(veg>3)^6

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/